Here we’ll see how to remove all occurences of a character from a string. For example, if we remove the character ‘o‘ from the string “The quick brown fox jumps over the lazy dog“, the result will be “The quick brwn fx jumps ver the lazy dg“. All four occurneces of ‘o’ removed from the string. The other characters will fill the holes created by removal of ‘o’.
Here is the C program.
#include <stdio.h>
void remove_char(char* str, char ch){
int i = 0, count = 0;
while (str[i + count] != '\0') {
/*Skipping the matched character...*/
if (str[i + count] == ch) count++;
str[i] = str[i + count];
i++;
}
str[i] = '\0';
}
int main() {
char str[256], ch;
printf("Enter a string: ");
fgets(str, sizeof(str), stdin);
printf("Enter a character to remove: ");
ch = getchar();
remove_char(str, ch);
printf("The string after removing %c: %s\n", ch, str);
return 0;
}
The above program takes a string and a character as input. Then it call the remove_char() function to remove the character and prints after removal.
Here is the output.
